-12x^2-24x+63=0

Solution for -12x^2-24x+63=0 equation:

-12x^2-24x+63=0

a = -12; b = -24; c = +63;
Δ = b2-4ac
Δ = -242-4·(-12)·63
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3600}=60$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-60}{2*-12}=\frac{-36}{-24}
=1+1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+60}{2*-12}=\frac{84}{-24}
=-3+1/2
$